1620A - Equal or Not Equal - CodeForces Solution


constructive algorithms dsu implementation *800

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Python Code:

num = int(input())

for a in range(num):
    k = input()
    e = k.count("E")
    num = k.count("N")
    if num==1:
        print("NO")
    else:
        print("YES")

C++ Code:

#include<bits/stdc++.h>
using namespace std;
#define ll long long
const int N=2e5+10;
int s[N];
int main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	int T;
	cin>>T;
	while(T--) {
		string s;
		cin>>s;
		cout<<(count(s.begin(),s.end(),'N')==1?"NO":"YES")<<'\n';
	}
	return 0;
}


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